answer me quick pls....
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4
Answer:
Step-by-step explanation:
X+5X-14=0
X=-7,2 zeros
Answered by
3
let, Alfa be it's first zero=a
and beta as it's second zero=B
as it is given, sum=a+B= -5
product=aB= -14
as we know, px^2 + qx. +c=0
a+B= -q/p
-5=-q/p q=5p ------>1
similarly,
aB=c/p
-14=c/p c=-14p --------->2
so, we get,
px^2 + 5px -14p=0
p( x^2 +5x -14p)=0
hence, polynomial is
and, it's zeros are
aB=-14. =>. a=-14/B
a+B=-5. =>. -14/B+B=-5
solve it you get, -7and 2
hope you like it
happy to answer u
and beta as it's second zero=B
as it is given, sum=a+B= -5
product=aB= -14
as we know, px^2 + qx. +c=0
a+B= -q/p
-5=-q/p q=5p ------>1
similarly,
aB=c/p
-14=c/p c=-14p --------->2
so, we get,
px^2 + 5px -14p=0
p( x^2 +5x -14p)=0
hence, polynomial is
and, it's zeros are
aB=-14. =>. a=-14/B
a+B=-5. =>. -14/B+B=-5
solve it you get, -7and 2
hope you like it
happy to answer u
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