Question

answer me step-by-step​

Answer 1

Answer:

step

step

step

step

step

Answer 2

Here's the explanation bud!

Explanation:

The divisibility test of 3 says that if the sum of the digits of a number is a multiple of 3, it is divisible by 3.

In this case,

31z5 is to be made a multiple of 3, meaning

$\frac{3+1+z+5}{3}=0$

$\frac{9+z}{3}=0$

This means that all possible digits for z are 0, 3, 6 and 9.

Answer: 0, 3, 6 and 9

I hope this proved to be helpful. :D