Question

answer me that question .
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Answer 1

QUESTION⤵️

ABCD is a rectangle whose length and breadth are 26 cm and 15 CM respectively. ADE is a triangle such that EF is perpendicular to AD and EF = 8 cm. calculate the shaded portion.

ANSWER ⤵️

AREA OF RECTANGLE = LENGTH× BREADTH

= 26CM×15CM

= 390CM^2

AREA OF TRIANGLE= 1/2×BASE × HEIGHT

= 1/2× 15× 8

= 60CM^2

AREA OF SHADED REGION= AREA OF RECTANGLE- AREA OF TRIANGLE

= 390- 60

$\longrightarrow\pink{= 330CM^2}$

$\huge\circ\mathcal\red{hope \: it \: helps}\circ$

Answer 2

Given : ABCD is a rectangle whose length and breadth are 26 cm and 15 cm respectively.

ADE is a triangle such that EF ⊥ AD and EF = 8 cm.

To Find : Calculate the area of the shaded portion.

Solution:

area of the shaded portion. = area of rectangle ABCD - area of triangle ADE

area of rectangle ABCD = AB x BC

= 26 x 15  

=  390 cm²

area of Δ ADE = (1/2) * AD * EF

AD = BC = 15 cm  , EF = 8 cm

=>  area of Δ ADE = (1/2) * 15 * 8

=>   area of Δ ADE = 60 cm²

area of the shaded portion. =  390 -60 = 330 cm²

area of the shaded portion. is 330  cm²

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