answer me the 2nd question
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1
x^2 + 1 / x^2 = 62
On adding 2 in both sides, we get
(x)^2 + (1 /x)^2 + 2 = 62 + 2
=> (x)^2 + (1 /x)^2 + 2 (x) ( 1/ x) = 64
=> ( x + 1/x)^2 = 64
=> x + 1/x = 8
On adding 2 in both sides, we get
(x)^2 + (1 /x)^2 + 2 = 62 + 2
=> (x)^2 + (1 /x)^2 + 2 (x) ( 1/ x) = 64
=> ( x + 1/x)^2 = 64
=> x + 1/x = 8
Answered by
0
Hi,
Here is your answer,
Given, (x +1/x) if (x² +1/x²) = 62
Now,
x²+ 1 / x²= 62
Now, we need to add 2 on b.s
→(x)² + (1/x)² + 2 = 62+2 ( Adding 2 on both sides)
→ x² + (1 /x)² + 2 × x (1/x) = 64
→ ( x + 1/x)² = 64
→ x + 1/x = 8
Hope it helps you !
Here is your answer,
Given, (x +1/x) if (x² +1/x²) = 62
Now,
x²+ 1 / x²= 62
Now, we need to add 2 on b.s
→(x)² + (1/x)² + 2 = 62+2 ( Adding 2 on both sides)
→ x² + (1 /x)² + 2 × x (1/x) = 64
→ ( x + 1/x)² = 64
→ x + 1/x = 8
Hope it helps you !
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