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Answered by
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15cans can be required for one wall and for 4walls is 60 cans
Answered by
1
15 cans required atleast for a single wall
so for 4 walls 60 cans
method. the total area of single wall= 20*12*6
=1440 m^2
no. of cans = total area/area by each can= 1440/96 = 15
therefore, 15 cans per wall
there fore 60 cans for 4 walls
so for 4 walls 60 cans
method. the total area of single wall= 20*12*6
=1440 m^2
no. of cans = total area/area by each can= 1440/96 = 15
therefore, 15 cans per wall
there fore 60 cans for 4 walls
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