Question

answer me these questions plz ​

Answer 1

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(3)Find the no. of sides of a regular polygon is each of its interior angle is 168°

Ans:-30sides

(4)If the sum of interior angles of a polygon is 3780°,find the no. of sides.

Ans:-Sum of interior angle of polygon =(n-2)180 3780=(n-1)180 n-1=21 n=21+1=22 therefore no. of sides are 22.

(5)The sum of interior angles of a regular polygon is twice the sum of its interior angles find the no. of sides.

Ans:-We know that

Sum of Interior angles of Polygon = 180(n-2)

Sum of Exterior angles of Polygon = 360

so 180(n-2)=2x360

Therefore, by solving we get n=6 sides.

(6)Find the measure of each exterior angle of regular polygon with 40 sides

Ans:-exterior angle =36040=9∘

(7)Find the sum of interior angles of a 11 sided polygon

Ans:-1620°

(8)In FIG ABCD is an isosceles trapezium,find x, y & z

Ans:-

Given :-

PQRS is an isosceles trapezium and ZP = 2x, ZS = 3x , ZQ=y

We have , PQRS an isosceles trapezium, then

PS = RQ

Since the Sum of adjacent angles are supplementary, Then

= ZP + ZS = 180°

= 2x + 3x = 180°

= 5x = 180°

= x = 180°/5

x= 36°

Now, PS = RQ

[PQRS is an isosceles trapezium]

ZP= ZQ

[Angle opposite to equal sides are equal ]

= 2x = y

= 2 x 36 = y

y = 72°

Hence, the values of x is 36° and y is 72º.

(9)Find the no. of diagonal in a 19 sided polygon

Ans:- 152

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