Question

Answer me this correctly!! Make sure to answer with detailed explanation

Answer 1

(Okki)

Q2.

$\large \rm \: a) \: \: \dfrac{5}{6} \times 2 \dfrac{3}{7}$

Solution

$\\ \leadsto \large \tt \: \: \dfrac{5}{6} \times \dfrac{17}{7} \ = \frac{85}{42}$

$\large \: \rm \: b) \: 2.73 \div 1 .3$

Solution

$\large \tt : \implies \: \: \dfrac{273}{100} \div \dfrac{13}{100} \\ \\ \\ \large \tt : \implies \: \: \dfrac{273}{ \cancel{100}} \times \dfrac{ \cancel{100}}{13} \\ \\ \\ \large \sf \: = \frac{273}{13}$

Q3.

a) 16 = 4 + 3(t + 2)

• Distributive Property

$\\ \large \sf \implies \: 16 = 4 + 3t + 6 \\ \\ \sf \large\implies \: 16 = 10 + 3t \\ \\ \large\sf \implies \: 16 - 10 = 3t \\ \\ \large\sf \implies \: 6 = 3t \\ \\ \large\sf \implies \: \frac{6}{3} = t \\ \\ \large \rm \therefore \: \: t = 2$

b) 12p - 5 = 25

$\large \rm \implies \: 12p = 25 + 5 \\ \\\large \rm \implies \: 12p = 30 \\ \\ \large \rm \implies \: p = \frac{30}{12} \\ \\ \\ \large \sf \therefore\: p = \frac{5}{2}$

Q8.

Given :

• AB // DE

• Angle ABC = 70°

$\large \rm \angle \: dgc = \: ? \\ \\ \large \sf \angle \: dgb = 70 \degree \\ \: \: \: (angles \: \: along \: \: transversal \\ are \: \: equal) \\ \\ \large \mapsto \sf \angle \: dgb + \angle \: dgc = 180 \degree \\ (linear \: \: pair) \\ \\ \large \sf \implies \: \angle \: dgc + 70 \degree = 180 \degree \\ \\ \large \sf \implies \: \angle \: dgc = 180 \degree - 70\degree$

Therefore,

• Angle DGC = 110°

• Angle DEF = 70°

Q9.

Angle BOA = 60°

60° + x = 180° (linear pair )

• x = 120°