answer me this question...
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Find out by the steps mentioned below. It is EASY.
Step-by-step explanation:
I'm letting you know the procedure.
To know the arclength of ADC major, we calculate what's the angle subtended at centre, i.e. refl. <AOD. We find that out by calculating <AOD (acute).
In order to find <AOD, we just find <AOB and multiply it by 2. Cause <AOB and <BOC are equal.
We know, triangle <AOB is right angled with <A = 90°. So applying some trig., we find,
cos<AOB = 4/10 = 2/5.
So from there we get <AOB.
Now that we have all that is reqd., we've solved it. What remains is (dreadful) calculation, which I'm leaving upto ya.
THANKS FOR YOUR ATTENTION. And BTW, if you think my answer was good, kindly thank me back.
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