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Answer:
2n
C
3
:
n
C
3
=12:1
⇒
n
C
3
2n
C
3
=
1
12
⇒
(2n−3)!3!
2n!
.
n!
(n−3)!3!
=12
⇒
(2n−3)!n!
2!(n−3)!
=12
⇒
6
2n(2n−1)(2n−2)
×
n(n−1)(n−2)
6
=12
⇒
(n−2)
4(2n−1)
=12
⇒2n−4=12n−24
⇒4n=20
∴n=5
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