answer my all questions i mark u brainlist
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Hello user☺☺
Refer to the attachement for the 1st answer.
_________________________________________________
Solution 2.
---------------
1. Since, the 1st is given as 12
so lets consider the other to be y.
Now, from very beginning we know that
3^2 + 4^2 = 5^2
Also, 12 is nothing but 4×3
So, the other numberw will be 4×4=16
and, 4×5=20
So, the triplets will be 12,16 and 20.
2. 13,5 and 12.
3. 21,28 and 35.
4. 6,4 and 10.
5. 0,6 and 6.
Hope this will help☺☺
Refer to the attachement for the 1st answer.
_________________________________________________
Solution 2.
---------------
1. Since, the 1st is given as 12
so lets consider the other to be y.
Now, from very beginning we know that
3^2 + 4^2 = 5^2
Also, 12 is nothing but 4×3
So, the other numberw will be 4×4=16
and, 4×5=20
So, the triplets will be 12,16 and 20.
2. 13,5 and 12.
3. 21,28 and 35.
4. 6,4 and 10.
5. 0,6 and 6.
Hope this will help☺☺
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Anonymous:
pls mark it brainliest
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