Math, asked by Hussain526, 9 months ago

answer my question

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Answered by venkatavineela3

0

Answer:

Step-by-step explanation:

LHS: 1-tanA/1+tanA

=(1-(1/cotA))/(1+(1/cotA))

=((cotA-1)/cotA)/((1+cotA)/cotA)

=cotA-1/cotA+1

=RHS

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