Math, asked by bishtvickykvs11, 1 year ago

answer my question


and get bainlist point

Attachments:

786PiyushSingh: (-12+7+5)^3=0^3=0

Answers

Answered by jaya1012
0
HELLO.....FRIEND!!

THE ANSWER IS HERE,

 = > \: ({ - 12})^{3} + ({7})^{3} + ({5})^{3}

This is in the form of

 = > \: {a}^{3} + {b}^{3} + {c}^{3}

So, Lets find a+b+c

=> -12+7+5

=> 0.

Here, a+b+c=0. So,

 = > \: {a}^{3} + {b}^{3} + {c}^{3} = 3abc

=> 3 (-12)(7)(5).

=> -1260.

2)

 = > ( {28})^{3} + ( { - 15)}^{3} + ( { - 13})^{3}

This is also in the form of

 {a}^{3} + {b}^{3} + {c}^{3}

So, Lets find a+b+c

=> 28-15-13

=> 0.

Here, a+b+c=0.So,

 = > {a}^{3} + {b}^{3} + {c}^{3} = 3abc

=> 3 (28)(-15)(-13)

=> 16,380.

:-)Hope it helps u.
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