Question

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Answer 1

Answer:

Step-by-step explanation:

Area of the region excluding ABD triangle = ΔABC - ΔABD

Area of ABC = $\sqrt{s(s-a)(s-b)(s-c)}$

s = a+b+c/2

= 16 + 48 + 52

= 116

\sqrt{s(s-a)(s-b)(s-c)} = $\sqrt{5048320}$

= 2246.8

Area of ABD = $\sqrt{s(s-a)(s-b)(s-c)}$

s = a+b+c/2

= 16 + 20 (pythogoras theorem) + 12 / 2

= 24

$\sqrt{s(s-a)(s-b)(s-c)}$ = $\sqrt{9216}$

= 96

Area of the region excluding ABD triangle = 2246.8 - 96

= 2150.8

Answer 2

Area of the region excluding ABD triangle = 2246.8 - 96= 2150.8 answer........

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