Question

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Answer 1

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Answer 2

SOLUTION

1

We know that, an equilateral ∆ has equal sides.

So, all sides are equal to 'a'.

Perimeter of ∆= 180° (given)

=) a+a+a= 180°

=) 3a= 180°

=) a= 180°/3

=) a= 60cm

Therefore,

$s = \frac{a + a + a}{2} = \frac{180}{2} = 90cm$

[2s= a+b+c] .........(1)

Area of an equilateral∆

=) √s(s-a)(s-a)(s-a) (by heroin's formula)

=)√90(90-60)(90-60)(90-60)

=)√30×3×30×30× 30

=) 30× 30√3

=) 900√3 cm^2

2

Let a= 122m

Let a= 122mb= 22m

Let a= 122mb= 22mc= 120m

We have, b^2 +c^2 = (22)^2 +(120)^2

=) 484 +14400

=) 14884 = (122)^2 = a^2

Hence, the side walls are in right triangular shape

The area of the ∆ side walls

=) (1/2× a× c

=) (1/2× 22× 120)

=) 11× 120

=) 1320m^2

Now,

Yearly rent= Rs. 5000per m^2

Monthly rent= Rs.5000× 1/12 per m^2

Company hired one of its walls for 3 months

Thus, rent paid by the company for 3 months

=) Rs.1320× 5000/12× 3

=) Rs.110× 5000× 3

=) Rs. 1650000. [answer]

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