Answer my question fast please...
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Answered by
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let mothers present age be x .
then son age will be x/2 .
A.T.Q
x+10= 3(x/2+10)
x+10= 3x/2 + 30
x-3x/2 = 30-10
x/2 = 20
x= 40
so mothers age will be 40 years.
and son will be 20 years old.
then son age will be x/2 .
A.T.Q
x+10= 3(x/2+10)
x+10= 3x/2 + 30
x-3x/2 = 30-10
x/2 = 20
x= 40
so mothers age will be 40 years.
and son will be 20 years old.
Answered by
0
HEYA MATE, HERE IS UR ANSWER
Let the present age of mother be x years .
Then Son's present age =1/2 of x
= x/2
Ten years ago
Son's age =x/2-10
=x-20/2
Mother's age=x-10
But according to the question
Mother's age =3×son's age
x-10=3×x-20/2
x-10=3x-60/2
By cross - multiplication
2 (x-10)=3x-60
2x-20=3x-60
2x-3x=-60+20
-x=-40
x=40
Therefore
=40 years
=40/2
= 20years
Let the present age of mother be x years .
Then Son's present age =1/2 of x
= x/2
Ten years ago
Son's age =x/2-10
=x-20/2
Mother's age=x-10
But according to the question
Mother's age =3×son's age
x-10=3×x-20/2
x-10=3x-60/2
By cross - multiplication
2 (x-10)=3x-60
2x-20=3x-60
2x-3x=-60+20
-x=-40
x=40
Therefore
=40 years
=40/2
= 20years
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