Question

ANSWER MY QUESTION!!!!!!!!


For Jacob's birthday, a basketball is wrapped in wrapping paper with no overlaps. The ball has a volume of 288π in3. What is the area of the wrapping paper (in terms of π)?

A) 64π in²
B) 92π in²
C) 144π in²
D) 256π in²

Answer 1

Step-by-step explanation:

4/3π r3=288π

4/3r3=288

4r3=288*3

r3=72*3

r=6

area of paper=πr² = π6*6=36π