Question

answer my question
I will do as brilliant who answer my question​

Answer 1

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Answer 2

$Given \\ </p><p>5^(2x^2) - 2.5^(x^2 +X + 6) \\ + 5^2x +12 = 0 \\ </p><p></p><p> \\ 25^(x^2) + 25 ^(X + 6) \\ = 2.5(x^2 + X + 6) \\ </p><p></p><p> \\ 10^(x^2 + x + 6)25^(x^2) \\ + 10^(x^2 + x + 6)25^(x + 6) \\ = 25^(x^2 +x +6) \\ </p><p>10^(x^2 + x + 6) 25^- (x + 6)+ \\ 25^(-x^2)= 1 \\ </p><p>using \: log \: on \: both \: side \\ </p><p>2x^2 +2 x + 12 \\ - (x+6)log25 - x^2log25 = 0 \\ </p><p>2(x^2+x+6) - \\ log25(x^2+x+6)=0 \\ </p><p>2(x^2 +x + 6)(1- log25) =0 \\ </p><p>x^2 + x + 6=0 \\ </p><p>x^2 + 3x - 2x + 6= 0 \\ </p><p>(x + 3)(x-2)= 0 \\ </p><p>so \\ </p><p>x =-3 \: and \: 2 \\ </p><p>value \: of \\ </p><p>at \: x=2 \\ </p><p>x^2 + x^3 = 2^2 \\ + 2^3 = 12</p><p> \: and \\ </p><p>at \: x= -3 \\ </p><p> \\ (-3)^2+ (-3)^3= \: 9 + 1/27 = 244/27</p><p></p><p>$