answer my question I will make you brainliest
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hey your answer is here
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1)(a+1/a)^3
apply the identity
(a+b)3=a3+b3+3ab(a+b)
so
(a+1/a)^3=a3+1/a3+3×a×1/a(a+1/a)
(a+1/a)3=a3+1/a3+3(a+1/a)
2)(2a-1/2a)^3
apply the identity
(a-b)3=a3-b3-3ab(a-b)
so
(2a-1/2a)3=8a3-1/8a3-3×2a×1/2a(2a-1/2a)
(2a-1/2a)=8a3-1/8a3-3(2a-1/2a)
-------;
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1)(a+1/a)^3
apply the identity
(a+b)3=a3+b3+3ab(a+b)
so
(a+1/a)^3=a3+1/a3+3×a×1/a(a+1/a)
(a+1/a)3=a3+1/a3+3(a+1/a)
2)(2a-1/2a)^3
apply the identity
(a-b)3=a3-b3-3ab(a-b)
so
(2a-1/2a)3=8a3-1/8a3-3×2a×1/2a(2a-1/2a)
(2a-1/2a)=8a3-1/8a3-3(2a-1/2a)
-------;
Anonymous:
hii
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