Question

Answer my question no 13.
First (right) answer will be brainliest.

Answer 1

Given Principal = 46875, R = 8.

(1) Interest for the 1st year:

We know that A = P(1 + r/100)^n

= > 46875(1 + 8/100)^1

= > 46875(1 + 8/100)

= > 46875(108/100)

= > 46875(27/25)

= > 50625.

We know that CI = A - P

= 50625 - 46875

= 3750.

(ii)

the amount standing to his credit at the end of the second year.

= > A = P(1 + r/100)^n

= 46875(1 + 8/100)^2

= 46875(108/100)^2

= 46875(27/25)^2

= 54675.

(iv) Amount at the end of 3rd year.

= > A = 46875(1 + 8/100)^3

= 46875(108/100)^3

= 46875(27/25)^3

= 59049.

(iii) Interest for the 3rd year:

= > CI = A - P

= 59049 - 54675

= 4374.

Hope this helps!