Question

answer my question please​

Answer 1

Answer:

18

Step-by-step explanation:

Given : a + b + c = 6

ab + bc + ca = 11

( a + b + c )² = a² + b² + c² + 2(ab + bc + ca)

(6)² = a² + b² + c² + 2(11)

a² + b² + c² = 36 - 22

a² + b² + c² = 14

a³ + b³ + c³- 3abc =(a + b + c)(a²+ b²+ c² - ab - bc - ac)

= (6) [a² + b² + c² - (ab + bc + ca)]

= (6) (14 - 11)

= (6) (3)

= 18