answer my question please
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as given in statement if
1/a + 1/b = 1 /(a+b)
so
(a+b)/ab = 1 /(a+b)
(a+b)^2 =ab
and
a^2+b^2=-ab .........(i)
now
a^3- b^3 = (a-b)(a^2+b^2+ab)
=(a-b)(-ab+ab). ........... from eq. I
=0 Ans.
1/a + 1/b = 1 /(a+b)
so
(a+b)/ab = 1 /(a+b)
(a+b)^2 =ab
and
a^2+b^2=-ab .........(i)
now
a^3- b^3 = (a-b)(a^2+b^2+ab)
=(a-b)(-ab+ab). ........... from eq. I
=0 Ans.
sona555:
thanks
ok
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