Question

Answer my question please.

Answer 1

Hey mate, here is your answer-:)

3x+ky=9 passes through the point (1,-2)
Hence, x=1 and y=-2


Then, 3x+ky=9
on putting x=1 and y=-2

3(1)+k (-2)=9

3-2k=9

-2k=9-3

-2k=6

k=6/-2

k=-3

Thus, the value of k is -3...

HOPE it helps to you!!!!

Answer 2

Hey there!!

According to the concept of straight line... Let a line be y = mx+c if passes through the point (h, k) then it will satisfy eqn y = mx + c...

From above concept.. :

Let the equation be : 3x + ky = 9 passes through (1,-2) then this pount will satisfy above equation..

So put x = 1 and y = -2 in equation 3x + ky = 9

=> 3(1) + k(-2) = 9

=> 3 -2k = 9

=> 2k = -6

=> k = -6/2 = -3

=> so k = -3..

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hope it will help u