Question

answer my question please
it's urgent
'brilliant' please answer

Answer 1

Heya !!

Here's your answer ..
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$here \: \: \frac{1}{x + 1} + \frac{1}{y + 1} = 10 \: \: and \: \: \frac{1}{x + 1} - \frac{1}{y + 1} = 4 \: \: are \: \: not \: \:pair \: \: of \: \: linear \: \: equation. \\ \\ take \: \: \frac{1}{x + 1} = a \: \: \: and \: \: \: \frac{1}{y + 1} = b \: \: in \: \: both \: \: eq. \\ \\ a + b = 10 \: \: \: \: \: .......(1) \\ \\ a - b = 4 \: \: \: \: \: .......(2) \\ \\ add \: \: eq.(2) \: \: and \: \: eq.(1) \\ \\ a + b = 10 \\ a - b = 4 \\ ......................... \\ 2a \: = \: 14 \\ \\ a = \frac{14}{2} \\ \\ a = 7 \\ \\ put \: \: value \: \: of \: \: (a) \: \: in \: \: eq.(1) \\ \\ 7 + b = 10 \\ \\ b = 10 - 7 \\ \\ b = 3 \\ \\ \frac{1}{x + 1} = a = 7 \\ \\ x + 1 = \frac{1}{7} \\ \\ x = \frac{1}{7} - 1 \\ \\ x = \frac{ - 6}{7} \\ \\ \\ \frac{1}{y + 1} = b = 3 \\ \\ y + 1 = \frac{1}{3} \\ \\ y = \frac{1}{3} - 1 \\ \\ y = \frac{ - 2}{3}$
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Hope it helps..
Thanks :)

Answer 2

it is your answer. ....♣♣♣♣
I think it will help you then you mark me brainlist please please please. ......♥♥♥♥