Question

answer my question please

the perimeter of a rectangular plot is 174 meter and its breath is 35 metre. find the length and the area of the plot ​

Answer 1

Step-by-step explanation:

Given,

Given, perimeter of rectangular plot = 174m

Given, perimeter of rectangular plot = 174mbreath = 35m

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?since,

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?since, parameter of rectangle = 2(l + b)

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?since, parameter of rectangle = 2(l + b) 174=2(l + 35 )

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?since, parameter of rectangle = 2(l + b) 174=2(l + 35 )174/2=l+5

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?since, parameter of rectangle = 2(l + b) 174=2(l + 35 )174/2=l+587 = l + 35

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?since, parameter of rectangle = 2(l + b) 174=2(l + 35 )174/2=l+587 = l + 35l = 87–35

Given, perimeter of rectangular plot = 174mbreath = 35m leangth = ?since, parameter of rectangle = 2(l + b) 174=2(l + 35 )174/2=l+587 = l + 35l = 87–35 l = 52m

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Answer 2

Answers

✩Length (l) of the rectangular Field = 52m.

✩Area of the rectangular Field = 1820 m².

Step-by-step explanation:-

GIVEN :-

Perimeter of a rectangular plot = 174m.

Breath of the rectangular plot = 35m.

TO FIND :-

1) Length of the rectangular plot

2) The area of the rectangular plot

ANSWERS

1) Length

Perimeter of a rectangle = 2 (l+b)

Here,

✳ Breadth(b) of the rectangular Field = 35m.

                           and

✳ Perimeter of the Rectangular Field = 174 m.

$\implies$

174 = 2 ( l+35 )

$\implies$

174 = 2l + 70

$\implies$

174 - 70 = 2l

$\implies$

104 = 2l

$\implies$

$\sf l =\dfrac{104}{2}$

$\implies$

✳ Length (l) of the rectangular Field = 52m.

The Rectangle is :-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 52m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 35m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

2)AREA

Area of a Rectangle = Length(l) × Breadth(b)

Here,

✳ Breadth(b) of the rectangular Field = 35m.

                      and

✳ Length(l) of the rectangular Field = 52m.

Area of the rectangular Field = 35 × 52

$\implies$

✳ Area of the rectangular Field = 1820 m².