Question

answer my questions in detail​

Answer 1

Step-by-step explanation:

our equation is:

32^4/5 +32^-4/5

now solve the terms one be one

now:32^4/5=(32^1/5)^4

since 32^1/5=2

thus,32^4/5=(32^1/5)^4

=2^4

=16

now we know that a^-b=(1/a)^b

since 32^-4/5=(1/32)^4/5

=1/(32)^4/5

since 32^4/5=16

so,32^-4/5=1/(32)^4/5

=1/16

since 32^4/5 +32^-4/5

=16 +1/16

by taking LCM and simplifying we get:

=(256+1)/16

=16 1/16

i.e option (B)

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Answer 2

EXPLANATION :

${32}^{ \frac{4}{5} } + {32}^{ - \frac{4}{5} }$

$= { ({2}^{5} })^{ \frac{4}{5} } + { ({2}^{5} })^{ - \frac{4}{5} }$

$= ({2})^{ \frac{4}{5} \times 5} + ( {2})^{ - \frac{4}{5} \times 5 }$

$= {2}^{4} + {2}^{ - 4}$

$= 16 + \frac{1}{16}$

$= \frac{256 + 1}{16}$

$= \frac{257}{16}$

here is the solution ↑

ANSWER :- (b). 16(1/16)

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