Question

answer my questions please

Answer 1

Answer:

Step-by-step explanation:

1st term of an application=5

Last number of an AP=-22

To find:term of last number

So,

(a)n=a+(n-1)d

-22=5+(n-1)-3

-22=5+(-3n+3)

-22-5=(-3n+3)

-27-3=(-3n)

-30=(-3n)

30=3n

n=

Answer 2

HOPE IT HELPS MARK AS BRAINLINEST