Question

Answer my questions please.
$\frac{ \ \sec(a) + \tan(a) }{ \sec(a ) - \tan(a) } = ( \frac{1 + \sin(a) }{ \cos(a) } ) {}^{2}$
​

Answer 1

Explanation:

taking

LHS

sec (a) + tan(a) => 1/cos(a) + sin(a)/ cos(a)

sec(a) - tan(a) 1/cos(a) + sin(a)/ cos(a)

taking LCM

=>. 1+sin(a) =>. 1+sin(a) × 1+sin(a)

1-sin(a) 1-sin(a) 1+sin(a)

=>. (1+sin(a))² => (1+sin(a))²

(1-sin²(a)) cos²(a)

=>. [ 1+sin(a) ]². = RHS

[ cos(a) ]

Answer 2

Explanation:

Sorry Don't have idea about this.