Physics, asked by Anonymous, 8 months ago

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Answered by Anonymous
1092

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ℓєτ τσταℓ ∂isταทcє вє x.

∂isταทcє σƒ ƒirsτ нαℓƒ= x/2.

sρєє∂ = v.

τiмє ταкєท,

τ1= x/2v.

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∂isταทcє σƒ 2ท∂ нαℓƒ= x/2

sρєє∂= 2v

τiмє ταкєท,

τ2= x/4v.

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ทσω sσℓviทg ρrσвℓєм:

1) αvєrαgє sρєє∂= τσταℓ ∂isταทcє τrαvєℓℓє∂/τσταℓ τiмє ταкєท.

αvєrαgє sρєє∂= ∂/τ

αvєrαgє sρєє∂= 4v/3

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2)мєαท sρєє∂= v+2v/2

мєαท sρєє∂= 3v/2

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τнєrєƒσrє,

αvєrαgє sρєє∂= 4v/3

мєαท sρєє∂= 3v/2

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Answered by goswamisunita509
1

Answer:

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