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Area of a triangle=30 cm
length of AD=60/13
AABC is right - angled at A. so, BC is definitely hypotenuse. let AB is base and AC is height of AABC. given, AB = 5cm , BC = 13cm and AC = 12c
now, area of triangle AABC = 1/2 x base x height
= 1/2 x length of AB x length of AC
= 1/2 x 5cm x 12cm = 30 cm2
hence, area of ABC = 30 cm
area of ABC = 1/2 x length of AB x length of AC =1/2 × length of BC x length of AD
=> 5cm x 12cm = 13cm x length of AD => 60/13 = 60/13 cm
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AD= 20.5cm
Ar∆(ABC)= 133.25cm²
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