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❒ answer
➥cosec10°-4sin(70°)=2.828≈3
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Answer:
cosec10 - 4sin70
= 1/sin10 - 4sin70
= (1 - 4sin70 * sin10)/sin10
= (1 - 2 * 2sin70 sin10)/sin10
= (1 - 2(cos60 - cos80))/sin10, cosA - cosB = -2sin[(A + B)/2] sin[(A - B)/2]
= (1 - 2cos60 + 2cos80)/sin10
= (1 - 2(1/2) + 2cos80)/sin10
= (1 - 1 + 2cos80)/sin10
= 2cos80 / sin10
= 2cos80 / cos(90 - 10), sinA = cos(90 - A)
= 2cos80 / cos80
= 2
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