Math, asked by Pynbiang12, 10 months ago

Answer No.8(1) Fast and correct.​

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Answered by mahenoorshk17
1

Step-by-step explanation:

LHS =( sin-cosec) (cos-sec)

= ( sin-1/sin) ( cos-1/cos)

= ( sin^2-1/sin ) ( cos^2-1/cos)

= ( cos^2 /sin) ( sin^2/cos )

=sin×cos ...... (1)

RHS = 1/tan+cot

= 1/ (sin/cos) +(cos/sin)

= 1/(sin^2 +cos^2/cos×sin)

=cos×sin

sin^2+cos^2

= sin×cos ....... (2)

From (1) and (2)

LHS=RHS

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