answer of 2nd question
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Let one side be x
Other side=x+8
Area=1/2h(a+b)
=1/2*7(x+x+8)=91
1/2*7(2x+8)=91
1/2*7*2(x+4)=91
7(x+4)=91
7x+28=91
7x=91-28
7x=63
x=9
Therefore one side=9dm
Other side=17dm.
durvang2006:
oh thanx whomsoever. you help me so much as it was so much urgent
Answered by
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Given,Area of trapezium = 91 dm^2.
Given,height = 7 dm.
Let the length of one parallel side is 'x'. Then the other side is x + 8 cm.
We know that Area of trapezium = (1/2) * (Sum of bases) * (Height).
⇒ 91 = (1/2) * (x + x + 8) * (7)
⇒ 91 = (1/2) * (2x + 8) cm * 7
⇒ 91 * 2 = (2x + 8) cm * 7
⇒ 182 = 14x + 56
⇒ 182 - 56 = 14x
⇒ 126 = 14x
⇒ x = 9.
Then,
⇒ x + 8
⇒ 17.
Therefore,
⇒ The two parallel sides are 9 dm and 17 dm.
Hope it helps!
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