Question

answer of d.2 plZ fast​

Answer 1

Answer:

Solve: ( D^2 - 4D + 1 ) y = x^2

We have to solve (D^2 - 4D + 1)y = x^2 The characteristic equation is p^2 - 4p + 1 = 0 p = 4±√(16 - 4)2 = 4±2√(3)2 = 2 ±√(3) Thus Complementary ...