Answer of Q . if x-y=13 & root x+ root y =13
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Let √x = a and √y = b ,
Given, √x + √y = 13
= > a + b = 13 -----: ( 1 )
According to the question :
= > x - y = 13
= > a² - b² = 13
= > ( a + b ) ( a - b ) = 13
Putting values from ( 1 ) ,
= > 13 ( a - b ) = 13
= > a - b = 13 / 13
= > a - b = 1
= > a = b + 1
Putting values in ( 1 ),
= > a + b = 13
= > b + 1 + b = 13
= > b = 6
So,
a + b = 13
a = 13 - 6
a = 7
Therefore,
√x = 7
So, x = 7²
x = 49
And,
√y = 6
So, y = 6²
y = 36
Given, √x + √y = 13
= > a + b = 13 -----: ( 1 )
According to the question :
= > x - y = 13
= > a² - b² = 13
= > ( a + b ) ( a - b ) = 13
Putting values from ( 1 ) ,
= > 13 ( a - b ) = 13
= > a - b = 13 / 13
= > a - b = 1
= > a = b + 1
Putting values in ( 1 ),
= > a + b = 13
= > b + 1 + b = 13
= > b = 6
So,
a + b = 13
a = 13 - 6
a = 7
Therefore,
√x = 7
So, x = 7²
x = 49
And,
√y = 6
So, y = 6²
y = 36
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