Question

answer of question number 4th of 11.3 of NCERT for class 8​

Answer 1

Answer:

R = 12,000

P = 6 %

T= 2 YRS

SI =P×R×T/100

SI

Is = 12000 × 6 × 2 /100

= 14400

A = p( 1+R /100) n

12,000(1+6/100) 2

Take it to the lowest form

Take it to the lowest form=6/100

Take it to the lowest form=6/100 will be 3 / 50

12000(50+3/50)2

12000 (53/50)2

12000×53/50×53/50

12000 ka 0 sa 50 ka 0 cut

12000 ka 0 sa 50 ka 0 cut again 12000 sa 50 ka 0 cut

= 337080/25

DIVIDE THIS

=13483.2

CI =A-P

13483.2 - 12000

= 1483.2

note / means upon

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