Question

answer of questions 17

Answer 1

distant travelled by the train =480km. let the speed of the train be X kmph time taken for the journey = 480/x given speed is decreased by 8kmph hence the new speed of train = (x-8)kmph time taken for the journey = 480 /(x-8) «480/(X-8)- 480/x=3. «480(x-x+8)/x(x-8)=3. «480/3*8=x*2-8*2. 1280=o on solving we get x=40 so speed of train is 40kmph

Answer 2

bro speed of train is 40 KM....