answer of sin5x-2sin3x+sinx/cos5x-cosx=tanx
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Answer:
(sin5x-2sin3x+sinx)/(cos5x-cosx)
=[{2sin(5x+x)/2cos(5x-x)/2}-2sin3x]/{2sin(5x+x)/2sin(x-5x)/2}
=(2sin3xcos2x-2sin3x)/{2sin3xsin(-2x)}
={2sin3x(cos2x-1)}/{-2sin3xsin2x}
=-(cos2x-1)/sin2x
=(1-cos2x)/sin2x
=2sin²x/2sinxcosx
=sinx/cosx
=tanx
[tex][/tex]
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