Math, asked by samhitaatreya7042, 1 year ago

Answer of Sudesh is twice as old as seema if six years is substacted from seema age and four years are added to sudesh age sudesh will be four times seema age how old were they three years old

Answers

Answered by AlienRapper
18
Let present age of Seema = x
Sudeesh = 2x
4( x-6) = 2x + 4
4x - 24 = 2x +4
4x - 2x=4+24
2x = 28
x=14
present age of Seema=14 yrs
present age of Sudesh= 28 yrs
3 yrs ago age of Seema = 11 yrs
3 yrs ago age of S
udesh =25 yrs

seema was 11 yrs old and sudesh was 25 yrs old 3 yrs ago

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Answered by Anonymous
2

Answer:

Let the age of Seema be x years.

Therefore, age of Sudesh will be 2x years.

It is given that, If six years is subtracted from Reha's age and four years added to Ishita's age :]

Age of Seema = x - 6

Age of Sudesh = 2x + 4

According to Question now,

➳ 4(x - 6) = 2x + 4

➳ 4x - 24 = 2x + 4

➳ 4x - 2x = 4 + 24

➳ 2x = 28

➳ x = 28/2

➳ x = 14 years

Therefore,

Present age of Seema = x = 14 years

Present age of Sudesh = 2x = 2(14) = 28 years

So,

Age of Seema 3 years ago = x - 3 = 14 - 3 = 11 years.

Age of Sudesh 3 years ago = 2x - 3 = 28 - 3 = 25 years.

Yayy we did it ._.

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