Question

Answer of this question .
how also?​

Answer 1

the answer is c. again

Answer 2

Answer:

$2-\sqrt{2}$

Step-by-step explanation:

Given :

To find the value of x , if

$x+\sqrt{x+\sqrt{x+\sqrt{x+\sqrt{x...} } } } = 2$

Solution :

$x+\sqrt{x+\sqrt{x+\sqrt{x+\sqrt{x...} } } } = 2$

By taking square root both the sides,

$\sqrt{x+\sqrt{x+\sqrt{x+\sqrt{x...} } } } = \sqrt{2}$

⇒ $x+\sqrt{2} = 2$

⇒ $x = 2-\sqrt{2}$