Question

Answer only 2,3 please mam did not explain lesson and gave me h.w.

Answer 1

Answer:

3

Step-by-step explanation:

using directly proportional concept

75÷45=5/x

on solving x=3

Answer 2

$2. given \: that \: 10 \: men \: can \: lay \: road \\ of \: 75km \: long \: in \: 5 \: days \\ therefore \\ \frac{75}{10 \times 5} = \frac{75}{50} \\ \frac{75}{10 \times 5} = \frac{15}{10} km \: per \: man \: per \: day \\ number \: of \: days \: in \: which \: 15 \: men \: lay \\ a \: road \: of \: 45km \: long \\ let \: number \: of \: days \: be \: \: d \\ \frac{45}{15 \times d} = \frac{15}{10} \\ 15 \times d = \frac{45 \times 10}{15} \\ d = \frac{3 \times 10}{15} \\ d = 2 \\ so \: 15 \: men \: can \: lay \: a \: road \: of \: 45km \: long \: \\ in \: 2 \: days$

$</p><p>3. 24 \: men \: working \: 8 \: hours \: a \: day \: \\ can \: do \: a \: piece \: of \: work \: in \: 15 \: days \\ total \: work \: done = 24 \times 8 \times 15 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2880 \\ number \: of \: days \: required \: by \: 20 \: men \: \\ working \: at \: 9 \: hours \: per \: a \: \: day \: \\ \frac{2880}{20 \times 9} = 16 \\ so \: no.of \: days \: required \: by \: 20 \: men \\ working \: at \: 9 \: hours \: per \: a \: day \: is \: 16 \: days$

Hope this helps you mate..........

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