Question

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Answer 1

Answer:

52 markit

Step-by-step explanation:

Given P = 1500 WV = 250 V i) Current drawn I = P V = 1500 250 PV=1500250 = 6A ii) Electric energy consumed by gyser in 50 hours = Power × time = 1500 × 50 = 75,000 Wh = 75 kWh Since 1 kWh = 1 unit 75 kWh = 75 units. ∴ Energy consumed = 75 units iii) Cost of one unit = 6.00 Cost 75 units = 75 × 6.00 Rs. 450.00Read more on Sarthaks.com - https://www.sarthaks.com/656394/electric-geyser-rated-1500-connected-mains-calculate-electric-current-energy-consumed

Answer 2

$\large\underline{\sf{Solution-}}$

$\large\underline{\sf{Given \: that \: - }}$

$\rm :\longmapsto\:A - 2B = \bigg[ \begin{matrix}1& - 2 \\ 3&0 \end{matrix} \bigg] - - - - (1)$

and

$\rm :\longmapsto\:2A - 3B = \bigg[ \begin{matrix}- 3& 3\\ 1& - 1 \end{matrix} \bigg] - - - (2)$

Now, multiply equation (1) by 2, we get

$\rm :\longmapsto\:2A - 4B = \bigg[ \begin{matrix}2& - 4 \\ 6&0 \end{matrix} \bigg] - - - - (3)$

Now, Subtracting equation (3) from equation (2), we get

$\rm :\longmapsto\:2A - 3B - 2A + 4B =\bigg[ \begin{matrix}- 3& 3\\ 1& - 1 \end{matrix} \bigg] - \bigg[ \begin{matrix}2& - 4 \\ 6&0 \end{matrix} \bigg]$

$\rm :\longmapsto\:B =\bigg[ \begin{matrix}- 3 - 2& 3 + 4\\ 1 - 6& - 1 - 0 \end{matrix} \bigg]$

$\rm :\longmapsto\:B =\bigg[ \begin{matrix}-5& 7\\ - 5& - 1 \end{matrix} \bigg]$

Hence,

$\bf :\longmapsto\:B =\bigg[ \begin{matrix}-5& 7\\ - 5& - 1 \end{matrix} \bigg]$

Additional Information :-

1. Matrix multiplication may or may not be Commutative.

2. Matrix multiplication is Associative, i.e. A(BC) = (AB)C

3. Matrix multiplication is Distributive, i.e. A(B + C) = AB + AC

4. Matrix multiplication is defined when number of columns of pre multiplier is equal to number of rows of post multiplier.

5. Matrix addition or subtraction is defined when order of both the matrices are same other wise matrix addition or subtraction is not defined.