Physics, asked by CHERRY2516, 6 months ago

Answer only if u know....with correct explanation plss​

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Answers

Answered by Anonymous
5

Answer:

Initial velocity of particle

u= 3 i^ +4 j^

Acceleration

a = 4 i^−3 j^

Final velocity after 1 second

v= u +at

where t=1 s⟹ v

= (3 i^ +4 j )+ (4 i^ −3 j^)×1= 7

i^ + j^

Speed after 1 second v

∣= 7 2 +1

= 50 m/s

Correct Answer✔✔

Answered by temporarygirl
3

Hola mate

Here is your answer -

Initial velocity of particle

u= 3 i^ +4 j^

Acceleration

a = 4 i^−3 j^

Final velocity after 1 second

v= u +at

where t=1 s⟹ v

= (3 i^ +4 j )+ (4 i^ −3 j^)×1= 7

i^ + j^

Speed after 1 second v

∣= 7 2 +1

= 50 m/s

Hope it helps you!

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