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Answer:
Initial velocity of particle
u= 3 i^ +4 j^
Acceleration
a = 4 i^−3 j^
Final velocity after 1 second
v= u +at
where t=1 s⟹ v
= (3 i^ +4 j )+ (4 i^ −3 j^)×1= 7
i^ + j^
Speed after 1 second v
∣= 7 2 +1
= 50 m/s
Correct Answer✔✔
Answered by
3
Hola mate
Here is your answer -
Initial velocity of particle
u= 3 i^ +4 j^
Acceleration
a = 4 i^−3 j^
Final velocity after 1 second
v= u +at
where t=1 s⟹ v
= (3 i^ +4 j )+ (4 i^ −3 j^)×1= 7
i^ + j^
Speed after 1 second v
∣= 7 2 +1
= 50 m/s
Hope it helps you!
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