Question

Answer only if you know​

Answer 1

Answer:

1. total oranges=540

initial student = X

initial oranges for 1 student = n

nx=540

(n-3) (x+30) =540

nx=(n-3)(x+30)

nx=nx+30n

30n=3x+90

x=30n-90 /3

x=10n-30

nx=540

n(10n-30) =540

n(n-3)=540

n2-3n-54=0

n2-9n+6n-54=0

n(n-9)+6(n-9)

(n-9)(n+6)=0

n-9=0

n=0+9=9

n+6=0

n=0-6=-6

2.