Math, asked by Anonymous, 6 months ago

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CLASS-6
CBSE....
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Answered by asuryaprakash5241
15

Answer:

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Answered by KittyFarily
31

\huge{\sf{\underline{\orange{\boxed{Answer  \: 1}}}}}

The disadvantage in company line segments by mere observation is that sometimes the difference in lengths between two line segments may not be adequate.

\huge{\sf{\underline{\orange{\boxed{Answer  \: 2}}}}}

When we measure of the length of a line segment by a ruler, there may be some errors due to its thickness and angular viewing. these errors can be removed by measuring a line segment with the help of a divider. hence, the use of divider is better than a ruler.

\huge{\sf{\underline{\orange{\boxed{Answer  \: 3}}}}}

See the Attachment for the 3rd Answer

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\huge{\sf{\underline{\orange{\boxed{Answer  \: 4}}}}}

\large\red{\underline{\pink{\rm\: Triangle A. :-}}}

  • ac + ab is larger than bc
  • ac + bc is larger than ab
  • ab + bc is larger than ac

hence, proved that sum of any two sides are always larger than third side.

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</p><p>\large\red{\underline{\pink{\rm\: Triangle B. :-}}}

  • de + fe is larger than df
  • df + fe is larger than de
  • df + de is larger than fe

hence, proved that sum of any two sides are larger than third side.

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\large\red{\underline{\pink{\rm\: Triangle C. :-}}}

  • gh + gi is larger than hi
  • hi + gi is larger than gh
  • hi + gh is larger than gi

hence, proved that sum of any two sides are larger than third side.

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\large\red{\underline{\pink{\rm\: Triangle D.:-}}}

  • jk + kl is larger than jl
  • jk + jl is larger than kl
  • jl + kl is larger than jk

hence, proved that sum of any two sides are larger than third side.

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\large\red{\underline{\pink{\rm\: Triangle E. :-}}}

  • mn + mo is larger than no
  • mn + no is larger than mo
  • mo + no is larger than mn

hence , proved that sum of any two sides are larger than third side.

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\huge{\sf{\underline{\orange{\boxed{Thank \:  you:}}}}}

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