Question

answer only if you know
who will if you post irrelavent you will be reported ✌️✌️​

Answer 1

Given:

$\large\rm{\dfrac{tx}{a} - \dfrac{y}{b} + t = 0 \implies \dfrac{\frac{y}{b}}{\frac{x}{a} +1}}$

$\large\rm{ \ }$

$\large\rm{ \dfrac{x}{a} + \dfrac{ty}{b} - 1 = 0}$

Answer:

eliminate t,

$\large\rm{ x^{2} b^{2} + a^{2} y^{2} = a^{2} b^{2}}$

which is clearly an ellipse

coming to ur next question ⚡

$\large\rm{ e^{2} = \dfrac{a^{2} - b^{2}}{a^{2}}}$

$\large\rm{ \dfrac{x^{2}}{16} + \dfrac{y^{2}}{12} = 1}$

next question ⚡

$\large\rm{ \tan 45° = \dfrac{\frac{b^{2}}{a}}{ae} }$

$\large\rm{ e = 1 - e^{2}}$

$\large\rm{ e = \dfrac{-1 + \sqrt{5}}{2} = 2 \ \sin \ 18°}$

Answer 2

Answer:

Hi Pavani

Naaku telisi nuvvu nenu type chesina second answer chudaledu..

Oka sari meeru Mee questions chusukondi..

Nenu answer ichanu