Question

answer only no spam otherwise will be reported..✖​

Answer 1

Step-by-step explanation:

((x^a+b)/(x^a))^a+b.((x^b+c)/x^a)^b-c.((x^c+a)/(x^b)^c-a

=((x^a²-b²).(x^b²-c²).(x^c²-a²)/((x^ac-bc).(x^ab-ac).(x^bc-ab))

=(x^a²-b²+b²-c²+c²-a²)/(x^ac-bc+ab-ac+bc-ab)

=x⁰/x⁰=1