Question

answer only with solutions​

Answer 1

Answer:

1 . 4 V

2 . 0.5A

3 . 0.2 A

4 . 2 V

5 . 3.2 ×10^-16.

Explanation:

1 . if 3 cells are connected in parllel, then efficient emf is the emf of high voltage .

2. Q = 30 c

t = 1 min = 60 sec

i = q / t

= 30 / 60

= 0.5 A

3. q = 60 c

t = 300s

i = 60 / 300

= 0.2 A

4 .same as QUSETION 1

5

Q = -1.6 × 10 ^-19 c

e = electron density = 2000

t = 1s

i = eq/t

=

$2 \times {10}^{3} \times 1.6 \times {10}^{ - 19} \div 1$

=3.2 × 10^-16 .

hope its useful.