Answer orrectly keeping signs in mind
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Answer:I)60cm
II)real, inverted, enlarged
III)-10cm
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Answer: Here you will have to apply the lens formula.
Explanation: Given that, u= -30cm; f= 20cm
By lens formula,
1/v - 1/u= 1/f
1/v= 1/f+1/u
1/v= 1/20-1/30
1/v= 3/60-2/60; Hence, 1/v=1/60 ∴v=60cm
The position of the image from lens is 60cm.
Magnification= v/u= 60/-30= -2
Size of image = Magnification * Size of object
= -2*5 = -10cm
Therefore, the image formed will be 60 cm or beyond 2F on the side opposite to the lens where the object is placed between f and 2f. Hence the image is real, inverted and magnified.
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