Math, asked by ananyachaturvedi1981, 16 days ago

Answer out with explanation and i will mark you as brainliest​

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Answers

Answered by rajjha391
1

Answer

option .no.2

Explanation

Sunil bought a 3 year old machine from Anil.

The price of machine at which Sunil bought = Rs. 7,29,000

Its value decreases by = 10 p.c.p.a.

Let the value of the machine when Anil purchased be 'x'.

Now we use the formula :

\text{Current value}=p(1-r)^t

p = purchased value, r = pcpa (10%) t = time (3 years)

7,29,000 = p(1-0.10)³

7,29,000 = p(0.9)³

7,29,000 = p × 0.729

p = \frac{7,29,000}{0.729}

p = 10,00,000 Rs.

Price of the machine was 10,00,000 when Anil bought it.

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