Question

Answer please............

Answer 1

Answer:

It will be 3(4a−3b)(b−3a)(2b−a)

Step-by-step explanation:

(4a−3b)³ −(3a−b)³ −(a−2b)³

=(4a−3b)³ +(b−3a)³ +(2b−a)³

Let,

x=4a−3b;y=b−3a;z=2b−a

On adding, x+y+z=0

∴x³ +y³ +z³ =3xyz

Subtituting x, y, z values, we get

= (4a−3b)³ +(b−3a)³ +(2b−a)³

= 3(4a−3b)(b−3a)(2b−a)